Skip to content

fix: 保护 @昵称(ID) 格式在命令参数解析时不被空格拆坏 #9307

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

Sign up for GitHub

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Open
Mer3y1338 wants to merge 2 commits into
base: master
Choose a base branch
from
Open

fix: 保护 @昵称(ID) 格式在命令参数解析时不被空格拆坏 #9307

Changes from 1 commit
Commits
Show all changes
2 commits
Select commit Hold shift + click to select a range
4d08d9b
fix: 保护 @昵称(ID) 格式在命令参数解析时不被空格拆坏
Mer3y1338 Jul 18, 2026
83ecbcd
fix(command): support non-numeric mention IDs
Mer3y1338 Jul 18, 2026
File filter

Filter by extension

Filter by extension
Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
6 changes: 4 additions & 2 deletions astrbot/core/star/filter/command.py
View file
Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -205,8 +205,10 @@ def filter(self, event: AstrMessageEvent, cfg: AstrBotConfig) -> bool:
if not ok:
return False

# 分割为列表
ls = message_str.split(" ")
# 分割为列表，同时保护 @昵称(ID) 格式不被空格拆坏
# 例如 "@Heaven Whisper(488267082) 64" 应拆为 ["@Heaven Whisper(488267082)", "64"]
# 而非 ["@Heaven", "Whisper(488267082)", "64"]
ls = re.findall(r"@[^@]+?\(\d+\)|[^\s]+", message_str)

@gemini-code-assist gemini-code-assist Bot Jul 18, 2026

Copy link
Copy Markdown
Contributor

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

medium

这里的正则表达式 r"@[^@]+?\(\d+\)|[^\s]+" 使用了 \d+ 来匹配括号中的用户 ID。虽然这对于 QQ 等使用纯数字 QQ 号作为 ID 的平台非常有效，但 AstrBot 作为一个多平台机器人框架，可能会接入其他平台的适配器（例如微信 wxid、Slack、Discord 或使用 UUID 的平台），这些平台的非数字用户 ID（可能包含字母、下划线、连字符等）将无法被该正则匹配，从而导致在这些平台上包含空格的昵称仍然会被拆分。

为了提高多平台兼容性，建议将 \d+ 替换为 [\w\-]+。这样既能支持包含字母、下划线、连字符等非数字字符的 ID，又因为不允许空格而避免了误匹配普通的带空格括号文本。

Suggested change
ls = re.findall(r"@[^@]+?\(\d+\)|[^\s]+", message_str)
ls = re.findall(r"@[^@]+?\([\w\-]+\)|[^\s]+", message_str)

# 去除空字符串
ls = [param for param in ls if param]
params = {}
Expand Down